Today, we're exploring an unconventional way to create a loop in Perl using more self-modifying code. This technique, while not practical for everyday use, showcases Perl's flexibility and power. Let's dive into this intriguing code snippet:
x#!/usr/bin/env perl
use |say|;
$_ = <<'EOF';
10;
s~(\d+)(?{ say qq($1) })~$1-1~e;
sleep 1;
$1 ? eval : say q(Countdown complete!);
EOF
eval;
This code creates a countdown from 10 to 1 without using any traditional loop constructs. Let's break it down:
We start by assigning a heredoc to the $_
variable. This heredoc contains the code that will be repeatedly evaluated.
The first line in the heredoc sets our starting number: 10.
The substitution operator s~~~
is the heart of our loop simulation:
xxxxxxxxxx
s~(\d+)(?{ say qq($1) })~$1-1~e;
This line does several things:
It matches a number (\d+)
It prints the matched number using a code block (?{ say qq($1) })
It replaces the number with itself minus one ($1-1)
The 'e'
flag at the end tells Perl to evaluate the replacement as code
We add a sleep 1;
to slow down the countdown for visual effect.
The final line in the heredoc is our exit condition:
xxxxxxxxxx
$1 ? eval : say q(Countdown complete!);
If $1
(our number) is truthy (non-zero), it evaluates the code again. Otherwise, it prints "Countdown complete!"
Finally, outside the heredoc, we have a single eval;
statement. This kicks off the whole process by evaluating the code in $_
.
When run, this script will count down from 10 to 1, pausing for a second between each number, and then print "Countdown complete!"
While this example is more of a curiosity than a practical coding technique, it illustrates Perl's flexibility and the creative ways we can bend the language to our will. It's a reminder of why Perl is often described as a "Swiss Army chainsaw" of programming languages!